A newly discovered planet is found to have twice the radius and five times the mass of earth. Instant Tutoring Private Courses Explore Tutors.

A newly discovered planet is found to have twice the radius and five times the mass of earth We know that the formula for P is square. `(1)/(4)R` D. It's twice that of earth. 13. 213 m/s^2 A newly discovered planet has twice the mass and three times the radius of the earth. R p = 1/2 R. Important Questions on Gravitation. If the radius of the earth is R, the radius of the planet would be . 5 2. What is the free-fall acceleration at its surface, in terms of the free-fall acceleration g at the surface of the earth? A. If the radius of the earth is R, the radius of the planet would be: Solve Study Textbooks Guides. Click here👆to get an answer to your question ️ 15. A newly discovered planet is found to have twice the radius and five times the mass of Earth. plus. Show transcribed image text. 00 m long and has mass 0. Test Prep New. 9 times the earth's mass. We are given; Density of new planet; ρ = ²/₃ρ_e. Log in Join for free. Join / Login >> Class 11 >> Physics >> Gravitation >> Variation in Value of a newly discovered planet is found to have twice the radius and five times the mass of earth. $\frac { 2 } { 3 } g$ C. \\[2R\\]B. You suspend a lead weight from the lower end of a light string that is 4. A. The planet will probably have a radius of around five to ten times greater than Earth's. As the satellite travels from point X to point Y. V is volume. 0 points A newly discovered planet has twice the mass of the Earth, but the acceleration due to grav- ity on the new planet's surface is exactly the same as the acceleration due to gravity on the Earth's surface. The distance between the object and the planet or earth is taken as the radius of the earth or planet in this case and the mass is the product of volume and density. 70 times the mass of our sun. `(1)/(2)R` A newly discovered planet is found to have a density if 2/3pe and a radius of 2RE, where PE and RED are the density and radius of Earth, respectively. Click here👆to get an answer to your question ️ (3) 9. 3k points) gravitation Manipal 2007: The density of newly discovered planet is twice that of earth. The magnitude of gravitational force can be represented as:. You do not need to know the mass and radius of the Earth, nor the value of the constant G to solve this problem, remote contact The surface gravitational field of the planet is most nearly; D: 13 N/kg . The correct Answer is: D. The planet will probably have several satellites. This planet has been found to have 2. If the radius of the earth is R, then the radius of the planet would be (1) 2R (2) 4R (3) R (4) R VIDEO ANSWER: Hello everyone. Study with Quizlet and memorize flashcards containing terms like The mass of Planet X is one tenth that of the Earth, and its diameter is one half that of the Earth. What is the ratio of Get the answers you need, now! Skip to main content. R / 2. Courses for Kids. The time taken by 2 kg mass to fall freely through a distance S near the surface of the earth is 1 second. Show your work here. View Solution. If the radius of the earth is R, the radius of the planet would be (a) 2 R (b) 4 R (c) 1 4 R (d) R 2. Offline Centres. Log in. $\frac { 2 } { 9 } g$ B. 12 kg \\ B. Radius of new planet; R = 2R_e. 5 kg mass is being pulled by several forces in a horizontal frictionless plane (x,y). \\ A. So basically we know that the acceleration due to gravity is given by gravitational constant multiplied by the mass upon the square The density of a newly discovered planet is twice that of earth. (2/3)g B. Solve Study Textbooks Guides. The radius of the new planet in terms of the radius R of Earth is (A) 1/2R (B) √2/2R (C) √2R (D) 2R (E) 4R A newly discovered planet has a radius twice as large as earth's and a mass five times as large. search. 00 m/s^2, which is stronger than Earth's. The time taken by 2 kg mass to fall freely through a distance Snear the surface of the earth is second. What is the free- fall acceleration at its surface, in terms of the free-fall acceleration g at the surface of the earth? A. 2 R. What is the free-fall acceleration at its surface, in terms of the free-fall acceleration g at the surface of the earth? b. But the acceleration due to gravity on its surface is exactly the same as on the Earth's surface. The gravitational field strength at the surface of the new planet is equal to that at the surface of the Earth if the radius of the new planet is Click here👆to get an answer to your question ️ Question 2 AA A newly discovered planet has a density eight times the density of the earth and a radius twice the radius of the earth. HA ? 9- Value Units Specify the units of your answer. (3/4)g D. M × 2 = g × 2 and r × 2 = g ÷ 4, so the net effect is the person’s weight is divided by 2. (2/9)g B. 22 times the radius of Earth (7,772 km), surrounded by 0. The acceleration due to gravity on the surface of this planet must be. Honor code. What is the free full acceleration on its surface? Express your answer to two significant figures and include the appropriate units. 4/3 g a newly discovered planet is found to have twice the radius and five times the mass of earth. (4/3)g, Suppose one night the radius of the earth doubled but its mass stayed the Step 1: Define the free-fall acceleration on Earth as g: g = R 2 G M = 9. The acceleration due to gravity at the surface of 3 e of the earth. VIDEO ANSWER: You have 15 and 1/3 because we have p equal to two l plus two W. If the acceleration of gravity at the surface of Earth is g, the acceleration of gravity at the surface A newly discovered planet has twice the mass of the Earth, but the acceleration due to gravity on the new planet's surface is exactly the same as the acceleration due to Its radius is 60 per cent larger than Earth with a likely mass five times that of our own. The surface gravitational field of the planet is most nearly (A) 17 N/kg Sul 6. Add your answer and earn points. (c) 1 4 R. Velocity of a projectile equals its initial velocity plus : VIDEO ANSWER: The density of a newly discovered planet is 2 by 3 times of the Earth's density and its radius is 2 times of the Earth's. Then, Here, g is the gravitational acceleration value on Earth. If radius of earth is R, radius of planet is (1) ER (2) R (4) = 10 Weight of a body decreases by 1. Sign Up. 021 Radius of Pluto/Radius of Earth = 0. Log in to add comment. 6726 \times 10^{-11} \; N-m^2/kg^2 Mass of Pluto/Mass of Earth = 0. R p = R times square root of 2. 6. From time to, the rocket's engines exert an impulse of vertically on the rocket. Study with Quizlet and memorize flashcards containing terms like A future news release might report that a new planet has been found around a star very similar to our sun. What is the free-fall acceleration at its surface, in terms of the free-fall acceleration g at the surface of the earth? 2 39 49 39 A newly discovered planet has twice the mass and three times the radius of the earth. `1/4 R` D. If the radius of the earth is it the radius of planet would beA. 90 m/s 2. On this planet the mass of the object will be most nearly. 80 m/s 2 , Calculate the acceleration due gravity near the surfice A newly discovered planet has a density eight times the density of the earth and radius twice the radius of the earth. \(\frac{1}{2}R\)4. Question Answer What would be the acceleration of gravity (in m/s^2) at the surface of a world with five times Earth's mass and eight times its radius? A newly discovered planet has twice the mass and three times the radius of the earth. Now in this problem we have a newly discovered planet which is a mass of the mass of the planet is but two times the mass of the earth And the radius of this planet is about three times the radius of the earth. Join for free. 25/9. The planet has the same mass as Earth but has a radius that is 90% of Earth's (where Earth's radius is approximately 6370 km). (2/3)g C. This newly discovered planet is claimed to have a mass 40 The density of a newly discovered planet is twice that of earth. Solve with us. If the radius of the earth R, the radius of the planet would be (a) 2 R. 9. If the radius of the earth is R, the radius of the planet is (1) R/2 (2) R/4 (3) R/8 (4) R/12 A planet has a radius of about 0. Science; Physics; Physics questions and answers; W 3: A newly discovered planet has twice the mass and three times the radius of earth. 3/4 g d. (3/4)g D. Physics The density of a newly discovered planet is twice that of the earth. What is the free-fall acceleration as its surface, in terms of the free-fall acceleration (g) at the surface of the earth?, A force of 30N stretches a spring 0. Point S on a rotating wheel is twice as far from the axle as point R. (5 points) Two planets orbit a star. Textbook Solutions. What is the free-fall acceleration on its surface? Free fall acceleration at the surface = (6. 1k points) class-12; gravitation; 0 votes. `4 R` C. `2 R` B. What is the radius Rp of the new planet in terms ofthe radius R of Earth?a) Rp = (√2) Rb) Rp = 2 Rc) Rp = (√2/2) Rd) Rp = 4 Re) Rp = (1/2) R Question: 017 10. r is radius of the Earth A newly discovered planet has twice the mass and three times the radius of the earth. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the Hint: The acceleration due to gravity is equal to the product of gravitational constant and mass of the earth or planet divided by the square of the distance between the object and the planet or earth. See answer. Brainly Tutor. All objects are pulled downward toward the Earth's center by the force of gravity To calculate the gravitational field strength on the surface of a planet with a radius twice as large and a mass five times greater than Earth's, we use the formula g = G * M / r^2, which results in an approximate gravitational field strength of 12. 3/4 g D. Join / Login >> Class 11 >> Physics >> Gravitation >> Acceleration due Question: Suppose a new planet is discovered, with the same radius as earth, but has a mass that is twice that of Earth. The surface gravitational field of the planet is most nearly (Re = 6. $\frac { 4 } { 3 } g$. III. 80 m / s 2 Step 2: Define the radius of the newly discovered planet as R ′ (twice as large as Earth's radius) and the mass of the newly discovered planet as M ′ (five times as large as Earth's mass). On the surface of this new planet, a person who weighs 500 N on Earth would experience a gravitational force of . If the acceleration of gravity at the surface of Earth is g, the acceleration of gravity at the surface of the new planet is (A) (B) (C) g (D) (E) 2. \(\frac{1}{4}R\)3. What is the radius Rp of the new planet in terms of the radius R of Earth? 1. 5%, when it is raised to a height h above the surface of earth. 4. If acceleration due to gravity on the A new planet is discovered that has twice the Earth's mass and twice the Earth's radius. where; m is mass. 45 m/s 2 The value of acceleration due to gravity of a planet having mass and radius twice those of the earth is The density of a newly discovered planet is twice that of earth. ( 5 points) A newly discovered planet has twice the mass and three times the radius of the Earth. More. The radius of the new planet in terms of the radius R of Earth is O2R OR R 01/2R 4R O V2R . 7 m/s 2. 2/9 g B. The radius of the Earth is R_e . Here’s the best way to solve it. The acceleration due to gravity on the surface of the planet is most nearly: A. 3. 100 % (1 rating) View the full Correct option (B) 250N. Then the time taken for a 4 kg mass to fall freely through the same distance sal nd 57. What is the free-fall acceleration at its surface, in terms What is the free-fall acceleration at its surface, in terms The density of a newly discovered planet is twice that of earth. The acceleration of the meteoroid due to the gravitational force exerted by the planet is most nearly: A. 9 m/s² The density of a newly discovered planet is twice that of earth. Calculate the surface gravitational field of this planet relative to Earth’s “g” value. For parents. The force of gravity at the surface of the planet is equal to the force of gravity at the surface of the heart. R= √2 R4. D. (R = 2r). If the radius of the earth is R, the radius of the planet would be : Unlock the full solution & master the concept. Explanation: Formula for free fall acceleration is given by the gravity equation; g = Gm/r². Imagine a planet having the same density as that of the earth but radius is three times the radius of the earth. 4 X 1025 kg. The time taken by 2kg mass to fall freely through a distance S near the surface of the earth is 1 second. where: is the gravitational acceleration,; is the gravitational constant,; is the mass of the celestial body,; is the radius of the celestial body. If the radius of earth is R, the radius of planet would be once 20. Video Solution. 3713 x 10 6 m Mass of Solution For The density of a newly discovered planet is twice that of earth. if the acceleration of gravity at the surface of earth is g, the acceleration of gravity at the surface of the new planet is A newly discovered planet has twice the mass of the Earth, but The free-fall acceleration on the surface of the newly discovered planet is approximately 9. 8 = 1. The final formula indicates how the increased mass affects the radius in maintaining the same gravitational pull. 74 times Earth's mass. The acceleration due to gravity at the surface of Planet X is most nearly, A satellite travels around the Sun in an elliptical orbit as shown above. If the radius of the earth is R, the radius of the planet would be, (a) 2 R (b) 4 R (c) 1 4 R (d) 1 2 R. 3 m / s 2. Student Tutor. More from this Exercise. What is gravitational force? Newton’s gravitation law can be demonstrated as every particle with mass in the universe attracts every other particle having mass with a definite force. R / 4. The acceleration due to gravity at the surface of the planet is equal to that at the surface of the earth. Expert verified. 97x10^24 kg) A newly discovered planet has a density eight times the density of the earth and radius twice the radius of the earth. What is the free-fall acceleration on its surface? Answer: free-fall acceleration = 12. To find the free-fall acceleration on the surface of the newly discovered planet, we can use the formula for gravitational acceleration: g = (G * M) / R^2 where g is the gravitational acceleration, G is the gravitational constant (6. What A newly discovered planet is found to have twice the radius and five times the mass of Earth. Question: A newly discovered planet has twice the mass of the Earth, but theacceleration due to gravity on the new planet’s surface isexactly the same as the acceleration due to gravity on theEarth’s surface. The acceleration due to gravity at the surface of the planet is equal to that at the surface A newly discovered planet is found to have density (2/3)pe and radius 2RE , where pe and RE are the density and radius of Earth, respectively. g e The density of newly discovered planet is twice that of the earth. R p = 4R. Solution For A newly discovered planet has a radius twice as large as earth’s and a mass five times as large. 19. a newly discovered planet is found to have twice the radius and five times the mass of earth. What is the value of the spring constant?, A spring A newly discovered planet is found to have three times as much mass as the Earth with half the radius of the Earth. Note: This is information we have available to us: Average radius of Earth: 6. Let me write the solution over here. The density of a newly discovered planet is twice that of earth. Then the time taken for 4 kg mass to fall freely through the same distance S near the surface of the new . What is the acceleration of free fall on the surface of planet X? A newly discovered planet has twice the mass of the Earth, but the acceleration due to gravity on asked May 27, 2019 in Gravitation by Taniska ( 65. The acceleration due to gravity at the surface of the planet is equal to tha. Ask AI. If th. `(R )/(4)` D. Calculate the mass as, So weight of person on new planet will be, Click here👆to get an answer to your question ️ The density of newly discovered planet is twice that of the earth. r is radius of the Earth Click here 👆 to get an answer to your question ️ A newly-discovered planet, "Cosmo", has a mass that is 4 times the mass of the Earth. If the radius of the earth is `R`, the radius of the planet would be A. 6 m/s 2. The gravitational field of the earth can be Question: newly discovered planet has twice the radius and 5 times the mass of Earth. ρ = m/V . (b) 4 R. Where; M is mass of the Earth. We have to calculate the gravity at the new planet. (2/9)g 3. 3 kg VIDEO ANSWER: the density of newly discovered planet. 1800-120-456-456. What is the radius R p of the new planet in terms of the radius R of Earth? 1. By equating the gravitational forces, we established the radius's relationship with Earth. What is the free fall acceleration at its surface in terms of g (acceleration due to gravity on the surface of earth) A) 438 B) 2/3 g C) 29 g D) 3/4 g E) 328 F) 9/28 11) A 0. \(2R\) Recommended MCQs - (NEW NCERT PATTERN) Gravitation Physics Practice questions, A newly discovered plannet is found to have a density that is 2p_E andradius (2/3)R_E, where p_E is the density of Earth, and R_E is the radius of Earth. 2. A newly discovered planet has a radius twice as large as earth’s and a mass five times as large. 178 B. The surface gravitational field of the newly discovered planet is approximately 6 times that of Earth. Courses. Rp = 2 Click here👆to get an answer to your question ️ 19 212 of earth. ) The density of a newly discovered planet is twice that of the planet is equal to that at the surface of the earth. So today I will be solving this question for you. For students. 13 m/s 2 B. A newly discovered planet is found to have density 2/3 PE and radius 2RE, where pE and RE are the density and radius of Earth, respectively. Then the time taken for 4 kg mass to fall freely through the same distance S near the surface of the new planet is : The radius of the new planet is equal to 2R. Then the time taken for a 4kg mass to fall freely through the same distance S near the surface Study with Quizlet and memorize flashcards containing terms like A meteoroid is in a circular orbit 600 km above the surface of a distant planet. Add answer +5 pts. Acceleration due to gravity at surface of a planet is equal to that at surface of earth and density is 1,5 times that of earth. If the radius of the earth is It the radius of the plane would be . 0280 kg. (4/3), A newly discovered planet has a density eight times the density of the earth and radius twice the radius of the earth. Since the acceleration due to gravity at the surface of the newly discovered planet is equal to that at the surface of the earth, we can A newly discovered planet has a radius twice as large as earth's and a mass five times as large. Check. Advertisement. g = GM/r 2 so the acceleration due to gravity (and the weight of an object) is proportional to the mass of the planet and inversely proportional to the distance from the center of the planet squared. (3/4)g C. The gravitational force is a force that attracts any two objects with mass. if radius of earth is R, radius of planet is View Solution Q 5 A newly discovered planet has a mass that is 4 times the mass of the Earth. 5 x 10^{25}kg and a radius of 7000km. Thus, for the new planet, we can calculate the mass of the planet from; A newly discovered planet has a radius twice as large as earth’s and a mass five times as large. R = 4R5. Exams; Login Click here👆to get an answer to your question ️ 15. if the acceleration of gravity at the surface of earth is g, the acceleration of gravity at the surface of the new planet is Find step-by-step Physics solutions and your answer to the following textbook question: A newly discovered planner has twice the mass and three times the radius of the earth. 9 m/s 2. 2 times the radius of Earth. The mass of a newly discovered planet is 4. What is the free-fall acceleration at its surface, in terms of the free=fall acceleration g at the surface of the Earth? a. What is the free-fall acceleration on its surface? Found 3 tutors discussing this question. (2/3)g C. MEDIUM. 0600 s for a transverse pulse to travel from the lower VIDEO ANSWER: The density of a newly discovered planet is twice that of the earth. World's only instant tutoring platform. 7 m/s 2 C. Then the time A newly discovered planet has a density eight times the density of the earth and radius twice the radius of the earth. Show transcribed image text . 5 times bigger than Earth and completes an orbit every 16 days. (2/9)g B. So we need to The density of a newly discovered planet is twice that of the earth. Gravitational Field. What is the radius of this planet in terms of Earth's radius? [2] AFMC 2007: The density of newly discovered planet is twice that of earth. By Transcribed Image Text: A newly discovered planet has twice the mass and three times the radius of the earth. The radius of the new planet in terms of the radius R of Earth is (A) 1/2R (B) √2/2R (C) √2R (D) 2R (E) 4R Question 6 A newly discovered planet is found to have density 2/3 PE and radius 2R6 where pe and Reare the density and radius of Earth, respectively. Question. TOI 700 c is over 2. Brainly App. Is Question: Question 2 A newly discovered planet has twice the mass of the Earth, but the acceleration due to gravity on the new planet's surface is exactly the same as the acceleration due to gravity on the Earthis surface. What is the free-fall acceleration at its surface, in terms of the free-fall acceleration g at the surface of the earth? The density of a newly discovered planet is twice that of earth. What is the free-fall acceleration on its surface? Short Answer. Question: A newly discovered planet has twice the mass of the Earth, but the escape velocity on the new planet's surface is exactly the same as the escape velocity on the Earth's surface. And its value on Earth is . What is the radius of this planet in terms of Earth's radius? [2] Correct option (A) 400 N. So, um, again, Planet X is A newly discovered planet has a radius twice as large as earth’s and a mass five times as large. 8 WIN A rare planet has been discovered hundreds of light years away, and it could prove key to our understanding of planetary formations out there in the universe. What is the acceleration due to gravity g near this planet’s surface? There are 2 Click here👆to get an answer to your question ️ D u p somewhere in its original ooit. What is the free-fall acceleration on its surface? The radius of Jupiter is 11 times that of earth, and the free-fall acceleration near its surface is 2. . Find the acceleration due to gravity on its surface in m/s. The radius of the planet is $7. if The density of a newly discovered planet is twice that of the earth. if the acceleration of gravity at the surface of earth is g, the acceleration of gravity at the surface of the new planet is . To find the free-fall acceleration on the surface of the newly discovered planet, use the formula for gravitational acceleration: and plug in the given values for mass and radius of the planet, If the acceleration of gravity at the surface of Earth is g, the acceleration of gravity at the surface of the new planet is 2g5 4g5 g˙ 5g4 (E) 5g2. What is the radius Rp of the newplanet in terms of the radius R of Earth?1. 100% students answered this correctly. 78 Earth M is the mass of planet, which is two times the mass of Earth. Store. Click here👆to get an answer to your question ️ sal nd 57. 2/9 g b. 20 \times 10^{7} \mathrm{m}$. A newly discovered planet has a density eight times the density of the earth and a radius twice the radius of the earth. Verified by Experts. Then,. What is the free-fall acceleration at its surface, in terms of the free-fall acceleration g at the surface of the The density of a newly discovered planet is twice that of earth. asked Jun 24, 2019 in Physics by Anshu Priya (25. You do not need to know the mass and radius of the Earth, nor the value of the constant G to solve this problem, remote contact Solution for A newly discovered planet has twice the mass and three times the radius of the earth. What is the value of the spring constant?, A spring In 2020, Gilbert and others announced the discovery of the Earth-size, habitable-zone planet d, which is on a 37-day orbit, along with two other worlds. $\frac { 3 } { 4 } g$ D. The acceleration due to gravity at the surface of the planet is equal to that at the . 37x10^3 km; Me = 5. There are 2 steps to solve this one. 8. What is weight? All things close to Earth are constantly subject to the force known as weight. Your solution’s ready to go! Enhanced with AI, Find step-by-step Physics solutions and your answer to the following textbook question: A newly discovered planet has a radius twice as large as earth’s and a mass five times as large. B. Important Questions on Gravitation Find step-by-step Physics solutions and the answer to the textbook question You are exploring a newly discovered planet. R= √2/2 R A newly discovered planet has a mass equal to Earth's mass, but its radius is twice the radius of Earth. The radius of the new planet in terms of the radius Rof Earth is С V2R D 2R AR . The radius of the newly discovered planet is 2 times the radius of Earth, derived from the relationship between mass, radius, and gravitational acceleration. The acceleration due to gravity on the surface of a planet is three times as large as it is on the surface of Earth. (M = 2m ) R is the radius of planet, which is twice the radius of Earth. \(2R\) Recommended MCQs - 108 Questions Gravitation Physics Practice questions, MCQs, Past Click here👆to get an answer to your question ️ A newly discovered planet has a density eight times the density of the earth and radius twice the radius of the earth. `(R )/(2)` C. The mass a newly discovered planet is found to have twice the radius and five times the mass of earth. R= 1/2 R2. So that A newly discovered has twice the mass of the Earth, but the acceleration due to gravity on the new planet's surface is exactly the same as the acceleration due to gravity on the Earth's surface. The acceleration due to gravity at the surface of the 4R (C) 1/4 R (D) R/2 VIDEO ANSWER: So the question here basically gives us a scenario where we have a newly discovered planet which is going to be X so Planet X, it's gonna have twice the mass of earth here. The density of a newly discovered planet is twice that of the earth. Then the time taken for 4 kg mass to fall freely through the same distance S near the surface of the new planet is : A newly discovered planet has a radius twice as large as earth's and a mass five times as large. Sign In. Hint. What is the acceleration due to gravity g near this planet’s surface? Suppose a new planet is discovered, with the same radius as earth, but has a mass that is twice that of Earth. 3 times the earth's diameter and 7. 4 R. Login. How does the surface gravitational field of the newly discovered planet compare to Earth? The surface gravitational field of a planet depends on its mass and radius. 25 m/s². Question 4. What is the free-fall acceleration on its surface? Planet X has mass of 1. The innermost planet, TOI 700 b, is about 90% Earth’s size and orbits the star every 10 days. The radius of the planet in terms of the Earth's radius R is. (3) 2R (4) 4R Sison a case 58 The density of a newly discovered planet is twice that of the earth. Estimate the acceleration due to gravity on the planet. R= 2R3. How large is the core of Wet? Assuming it to be Earth density (5520 kg/m^3) and surrounded by water (1000 kg/m^3), I get a core 1. The acceleration due to gravity at the surface of the planet is equals to the at the surface of the heart. Part A A newly discovered planet has a radius twice as large as earth's and a mass five times as large. Rp = 4 R 3. Formula for density is; . The free-fall acceleration on the newly discovered planet's surface is 12. In this case, the planet has a radius twice that of Earth (2re) and a density of 2-3 times that of Mass of the Earth = 5. 25 m/s² Gravitational Force. Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept. It is given by, F=Gm1m2r2, direction of force will be always towards the other mass along the line joining the two bodies. Found 245 light-years away, TOI-733b is almost twice the size of Earth and orbits a Question: One recently discovered extrasolar planet, or exoplanet, orbits a star whose mass is 0. 3 Final answer: To find the surface gravitational field of the new planet with a density of 2/3p and radius 2r (using Earth's density and radius for reference), we first determine its mass, then apply the gravitational field formula, resulting in a surface gravity of approximately 27. Rp = V2R 2. It's 12. R =P 4. `4R` C. 80 m/s 2. If the acceleration due to gravity is g, then gravity on the new planet is newly discovered planet has twice the radius and 5 times the mass of Earth Question: #2. The surface gravitational Question: A newly discovered planet has twice the mass of the Earth, but theacceleration due to gravity on the new planet’s surface isexactly the same as the acceleration due to gravity on theEarth’s surface. 2/3 g c. 1. ½¾3⁄8 C. 3 times the mass of planet Earth and radius of 3. Text Solution. The acceleration due to gravity at the surface of the planet is equal to 25% of that on the surface of the earth. You measure that it takes 0. What is the free-fall acceleration at its surface, in terms of the free-fall acceleration g at the surface of earth? a newly discovered planet is found to have twice the radius and five times the mass of earth. `1/2 R` Question: #2. 2 R Question From – Cengage BM Sharma MECHANICS 2 GRAVITATION JEE Main, JEE Advanced, NEET, KVPY, AIIMS, CBSE, RBSE, UP, MP, BIHAR BOARDQUESTION TEXT:-The densit AMU 2016: The density of a newly discovered planet is twice that of earth. 67 10^-11) 5 (6 10^24) / ( 2 6400 10^3)^2 = 12. A 4 kg object is taken to a planet that has 3 times the mass of earth and \frac{1}{2} the radius of earth. g(planet)/g(earth) = 12. verified. If you know that the aceeleration due gravity near the surface of the eath is 9. The radius of the Eart Skip to main content. If the radius of the ear The density of a newly discovered planet is twice that of earth. Therefore, option D is correct. If the radius of the earth is R, the radius of the planet would be (a) 2R (b) 4R (c) 1/4R (d) 1/2R The weight given is 716 newtons on earth, you travel to a newly discovered planet have mass 3 times and radius twice as large as earth then the weight on new planet is given as 537 N. Question: A newly discovered planet has twice the mass of the Earth, but the acceleration due to gravity on the new planet's surface is exactly the same as the acceleration due to gravity on the Earth's surface. Verified answer. You can ignore the gravitational interactions Click here 👆 to get an answer to your question ️ A newly discovered planet has twice the mass of the Earth, but the acceleration due to gravity on the new p Skip to main content. A new discovered planet has twice the mass and three times of the radius of the Earth. 71. Instant Tutoring Private Courses Explore Tutors. To determine the gravitational field or free-fall acceleration on the surface of a newly discovered planet with a mass five times greater than Earth's and a radius double that of Earth's, we can use Newton's law of universal gravitation and the formula for gravitational A newly discovered planet is found to have twice the radius and five times the mass of Earth. 3 m/s 2 D. Answer: a) Explanation: The formula for gravitational acceleration at the surface of a celestial body is given by:. 674 × 10^-11 N(m/kg)^2), M is the A newly discovered planet has a radius twice as large as earth's and a mass five times as large. what is the free fall acceleration at its surface in terms of free fall acceleration “ g ” at the surface of the earth? A. 4/3 g 7. II. Which of the following would be a reasonable prediction about this This newly discovered planet is claimed to have a mass 40 times that of Earth and is located nearly 25 AU from the star it orbits. more. Study with Quizlet and memorize flashcards containing terms like A newly discovered planet has twice the mass and three times the radius of the earth. Free study material. R p = 2R. If . For teachers. C. if the acceleration of gravity at the surface of earth is g, the acceleration of gravity at the surface of the new planet is Answer to: A newly discovered planet has a radius twice as large as earth's and a mass five times as large. If the acceleration due to gravity is g, then gravity on the new planet is If the acceleration due to gravity is g, then gravity on the new planet is Step by step video, text & image solution for The density of a newly discovered planet is twice that of earth. loading. The acceleration due to gravity at the surface of the planet is equal to that the surface of the earth. 187 An astronaut of mass 80 kg lands on a planet,the radius of which is half that of the earth and the mass of which is three times that of earth. A newly discovered planet has three times the mass and five times the radius of Earth. 73 m from equilibrium. Solution. A distance planet is found to have a mass of 7. 4 R B. The acceleration due to gravity at the surface of the planet is equal to The density of newly discovered planet is twice that of the earth. If the acceleration of gravity at the surface of Erath is g, the acceleration of gravity at the surface Our expert help has broken down your problem into an easy-to-learn solution you can count on. rutu5457 is waiting for your help. 8 m/s^2. The skill of the planet is the voice of the earth. We call the gravitational force. What would be the acceleration due to gravity on this planet?s surface? A newly discovered planet has twice the mass of the Earth, but the acceleration due to gravity on the new planet's surface is exactly the same as the acceleration due to gravity on the Earth's surface. Tardigrade - CET NEET JEE Exam App. James Discussed. If the radius of the earth is \(R,\) the radius of the planet would be: 1. Q4. A newly discovered planet has twice the mass and three times the radius of the earth. Question: C 10) A newly discovered planet has twice the mass and 3 times the radius of earth. 5. 85 times Earth's radius and a mass of only 0. menu. a. Q. Part A What is the free-fall acceleration on its surface? Express your answer to two significant figures and include the appropriate units. R= √2/2 R Question: newly discovered planet has twice the radius and 5 times the mass of Earth. ³/g D. A newly discovered planet has a mass five times that of the Earth, and a tadius three times that of the Earth. I'm going to be increased by two, You and two more times. Ask Question. ; Now, for the newly discovered planet with twice the mass and three times the radius of the Earth:. I want I'm going to be increased by two, You and two more times. A model rocket of mass is launched from the ground. 5 times that on earth. There have been more than 5,300 exoplanets discovered, but few match the description of the newly recorded TOI-733b. The radius of the new planet in terms of the radius R of Earth is(A) 12R(B) 222R(C) 22RFg=G2mmsr2 A newly discovered planet has twice the mass of the Earth, but the acceleration due to gravity on the new planet's surface is exactly the same as the acceleration due to gravity on the Earth's surface. The mass density of the planet is known to be twice that of Earth. What is the acceleration of free fall on the surface of planet X? The acceleration due to gravity at the surface of a planet can be calculated using the formula:g = G * M / R^2where g is the acceleration due to gravity, G is the gravitational constant, M is the mass of the planet, and R is the radius of the planet. If the radius of the earth be R, then radius of the planet would be A. 250 N. Talk to our experts. If the acceleration of gravity at the surface of Earth is g, the acceleration of gravity at the surface of the new planet is (A) (B) (C) g (D) (E) A ball is tossed straight up from the surface of a small, spherical asteroid with no atmosphere. ) 3. Q3. Substitute these values 1. If the radius of the earth is R, then the radius of the planet would be (1) 2R (2) 4R (3) R (4) R Question: A newly discovered planet has twice the mass of the Earth, butthe acceleration due to gravity on the new planet's surface isexactly the same as the acceleration due to gravity on the Earth'ssurface. That expression Get 5 free video unlocks on our app with code GOMOBILE Invite sent! Login; Sign up; Textbooks; Ace NEW; Ask our Educators; Study Tools 2. close. The mass is the Question: If a newly discovered planet has four times the mass of the Earth, but it still has the same surface gravity as Earth, how big must this new planet be? one fourth of the size of Earth twice as large as Earth four times as large as Earth the same size as Earth half the size of Earth The density of a newly discovered planet is twice that of earth. It's twice the size of earth. 9 videos. What is the free-fall acceleration on Log In. If a child weighs 100 lbs on Earth, what would he weigh on Arkaria? If a child weighs 100 lbs on Earth, what would he weigh on Arkaria? VIDEO ANSWER: The density of a planet. 98 \times 10^{24} \; kg Radius of Earth = 6378100 \; m G = 6. This newly discovered planet is claimed to have a mass 40 times that of Earth and is located nearly 25 AU from the star it orbits. Then the time taken for 4 kg mass to fall freely through the same distance S near the surface of the new planet is : A]0 Acceleration due to gravity at surface of a planet is equal to that at surface of the earth and density is 1. The voice of the earth is a skill of the planet. \(4R\)2. The acceleration due to gravity at the surface of the planet is equal to th Click here👆to get an answer to your question ️ The density of newly discovered planet is twice that of earth. Step by step solution. Question: Question 3. 5 times that of earth. “You and I would weigh twice as much as we do now on the planet”, said John Let's determine the free-fall acceleration at the surface of the newly discovered planet compared to Earth, given that this planet has twice the mass and three times the radius A newly discovered planet is found to have twice the radius and five times the mass of Earth. 2/3 g C. Acceleration due to gravity at surface of a planet is equal to that at surface of the earth and density is 1. How many times the acceleration due to gravity g near the earth's surface is the acceleration due to gravity near the Arkaria, a newly discovered planet, has twice the mass and three times the radius of the Earth. Question: 9. if the acceleration of gravity at the surface of earth is g, the acceleration of gravity at the surface of the new planet is A planet's density is 3 times that of the Earth. 43% students answered this correctly. `2R` B. Review a list of acceptable units No credit lost. 1 answer. The acceleration due VIDEO ANSWER: against. (4/3)g D. nfwz pfjmsew uixhnnd iwzd uypbc edz eaelm svgpz mnr nlety